10k-(2k-7)=3(k+31)

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Solution for 10k-(2k-7)=3(k+31) equation: 



10k-(2k-7)=3(k+31)

We move all terms to the left:

10k-(2k-7)-(3(k+31))=0

We get rid of parentheses

10k-2k-(3(k+31))+7=0



We calculate terms in parentheses: -(3(k+31)), so:

3(k+31)

We multiply parentheses

3k+93

Back to the equation:

-(3k+93)



We add all the numbers together, and all the variables

8k-(3k+93)+7=0

We get rid of parentheses

8k-3k-93+7=0

We add all the numbers together, and all the variables

5k-86=0

We move all terms containing k to the left, all other terms to the right

5k=86

k=86/5

k=17+1/5

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