10k-2k(k+3)=10

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Solution for 10k-2k(k+3)=10 equation: 



10k-2k(k+3)=10

We move all terms to the left:

10k-2k(k+3)-(10)=0

We multiply parentheses

-2k^2+10k-6k-10=0

We add all the numbers together, and all the variables

-2k^2+4k-10=0

a = -2; b = 4; c = -10;
Δ = b2-4ac
Δ = 42-4·(-2)·(-10)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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