10m(m+2)=7m-4

Solution for 10m(m+2)=7m-4 equation:

10m(m+2)=7m-4

We move all terms to the left:

10m(m+2)-(7m-4)=0

We multiply parentheses

10m^2+20m-(7m-4)=0

We get rid of parentheses

10m^2+20m-7m+4=0

We add all the numbers together, and all the variables

10m^2+13m+4=0

a = 10; b = 13; c = +4;
Δ = b2-4ac
Δ = 132-4·10·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*10}=\frac{-16}{20}
=-4/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*10}=\frac{-10}{20}
=-1/2
$