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10m^2=7m+17
We move all terms to the left:
10m^2-(7m+17)=0
We get rid of parentheses
10m^2-7m-17=0
a = 10; b = -7; c = -17;
Δ = b2-4ac
Δ = -72-4·10·(-17)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-27}{2*10}=\frac{-20}{20} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+27}{2*10}=\frac{34}{20} =1+7/10 $
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