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10n^2+16n+6=0
a = 10; b = 16; c = +6;
Δ = b2-4ac
Δ = 162-4·10·6
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*10}=\frac{-20}{20} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*10}=\frac{-12}{20} =-3/5 $
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