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10n^2-30n-108=0
a = 10; b = -30; c = -108;
Δ = b2-4ac
Δ = -302-4·10·(-108)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{145}}{2*10}=\frac{30-6\sqrt{145}}{20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{145}}{2*10}=\frac{30+6\sqrt{145}}{20} $
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