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10n^2=35n
We move all terms to the left:
10n^2-(35n)=0
a = 10; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·10·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*10}=\frac{0}{20} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*10}=\frac{70}{20} =3+1/2 $
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