10n=0(2n2)

Solution for 10n=0(2n2) equation:

10n=0(2n^2)

We move all terms to the left:

10n-(0(2n^2))=0

determiningTheFunctionDomain
10n-02n^2=0

We add all the numbers together, and all the variables

-02n^2+10n=0

We add all the numbers together, and all the variables

-2n^2+10n=0

a = -2; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-2)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-2}=\frac{-20}{-4}
=+5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-2}=\frac{0}{-4}
=0
$