10p(2)+8p=61

Solution for 10p(2)+8p=61 equation:

10p(2)+8p=61

We move all terms to the left:

10p(2)+8p-(61)=0

We add all the numbers together, and all the variables

10p^2+8p-61=0

a = 10; b = 8; c = -61;
Δ = b2-4ac
Δ = 82-4·10·(-61)
Δ = 2504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2504}=\sqrt{4*626}=\sqrt{4}*\sqrt{626}=2\sqrt{626}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{626}}{2*10}=\frac{-8-2\sqrt{626}}{20}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{626}}{2*10}=\frac{-8+2\sqrt{626}}{20}
$