10p+0-11-p=-2(2p+4)-3(2p-2)

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Solution for 10p+0-11-p=-2(2p+4)-3(2p-2) equation:



10p+0-11-p=-2(2p+4)-3(2p-2)
We move all terms to the left:
10p+0-11-p-(-2(2p+4)-3(2p-2))=0
We add all the numbers together, and all the variables
9p-(-2(2p+4)-3(2p-2))-11=0
We calculate terms in parentheses: -(-2(2p+4)-3(2p-2)), so:
-2(2p+4)-3(2p-2)
We multiply parentheses
-4p-6p-8+6
We add all the numbers together, and all the variables
-10p-2
Back to the equation:
-(-10p-2)
We get rid of parentheses
9p+10p+2-11=0
We add all the numbers together, and all the variables
19p-9=0
We move all terms containing p to the left, all other terms to the right
19p=9
p=9/19
p=9/19

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