10p+9-11-p=-2(2-p+4)-3(2p-2)

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Solution for 10p+9-11-p=-2(2-p+4)-3(2p-2) equation:



10p+9-11-p=-2(2-p+4)-3(2p-2)
We move all terms to the left:
10p+9-11-p-(-2(2-p+4)-3(2p-2))=0
We add all the numbers together, and all the variables
10p-p-(-2(-1p+6)-3(2p-2))+9-11=0
We add all the numbers together, and all the variables
9p-(-2(-1p+6)-3(2p-2))-2=0
We calculate terms in parentheses: -(-2(-1p+6)-3(2p-2)), so:
-2(-1p+6)-3(2p-2)
We multiply parentheses
2p-6p-12+6
We add all the numbers together, and all the variables
-4p-6
Back to the equation:
-(-4p-6)
We get rid of parentheses
9p+4p+6-2=0
We add all the numbers together, and all the variables
13p+4=0
We move all terms containing p to the left, all other terms to the right
13p=-4
p=-4/13
p=-4/13

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