10p-2-p=2(2p+4)-3(2p-2)

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Solution for 10p-2-p=2(2p+4)-3(2p-2) equation: 



10p-2-p=2(2p+4)-3(2p-2)

We move all terms to the left:

10p-2-p-(2(2p+4)-3(2p-2))=0

We add all the numbers together, and all the variables

9p-(2(2p+4)-3(2p-2))-2=0



We calculate terms in parentheses: -(2(2p+4)-3(2p-2)), so:

2(2p+4)-3(2p-2)

We multiply parentheses

4p-6p+8+6

We add all the numbers together, and all the variables

-2p+14

Back to the equation:

-(-2p+14)



We get rid of parentheses

9p+2p-14-2=0

We add all the numbers together, and all the variables

11p-16=0

We move all terms containing p to the left, all other terms to the right

11p=16

p=16/11

p=1+5/11

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