10p-2=-2(2p+4)-3(2p-2)

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Solution for 10p-2=-2(2p+4)-3(2p-2) equation: 



10p-2=-2(2p+4)-3(2p-2)

We move all terms to the left:

10p-2-(-2(2p+4)-3(2p-2))=0



We calculate terms in parentheses: -(-2(2p+4)-3(2p-2)), so:

-2(2p+4)-3(2p-2)

We multiply parentheses

-4p-6p-8+6

We add all the numbers together, and all the variables

-10p-2

Back to the equation:

-(-10p-2)



We get rid of parentheses

10p+10p+2-2=0

We add all the numbers together, and all the variables

20p=0

p=0/20

p=0

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