10q+2q+5=2(q-3)

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Solution for 10q+2q+5=2(q-3) equation: 



10q+2q+5=2(q-3)

We move all terms to the left:

10q+2q+5-(2(q-3))=0

We add all the numbers together, and all the variables

12q-(2(q-3))+5=0



We calculate terms in parentheses: -(2(q-3)), so:

2(q-3)

We multiply parentheses

2q-6

Back to the equation:

-(2q-6)



We get rid of parentheses

12q-2q+6+5=0

We add all the numbers together, and all the variables

10q+11=0

We move all terms containing q to the left, all other terms to the right

10q=-11

q=-11/10

q=-1+1/10

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