10q+3q+5=2(q-6)

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Solution for 10q+3q+5=2(q-6) equation: 



10q+3q+5=2(q-6)

We move all terms to the left:

10q+3q+5-(2(q-6))=0

We add all the numbers together, and all the variables

13q-(2(q-6))+5=0



We calculate terms in parentheses: -(2(q-6)), so:

2(q-6)

We multiply parentheses

2q-12

Back to the equation:

-(2q-12)



We get rid of parentheses

13q-2q+12+5=0

We add all the numbers together, and all the variables

11q+17=0

We move all terms containing q to the left, all other terms to the right

11q=-17

q=-17/11

q=-1+6/11

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