10s+52-2(2s-6)=1+7(s+9)

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Solution for 10s+52-2(2s-6)=1+7(s+9) equation: 



10s+52-2(2s-6)=1+7(s+9)

We move all terms to the left:

10s+52-2(2s-6)-(1+7(s+9))=0

We multiply parentheses

10s-4s-(1+7(s+9))+12+52=0



We calculate terms in parentheses: -(1+7(s+9)), so:

1+7(s+9)

determiningTheFunctionDomain
7(s+9)+1

We multiply parentheses

7s+63+1

We add all the numbers together, and all the variables

7s+64

Back to the equation:

-(7s+64)



We add all the numbers together, and all the variables

6s-(7s+64)+64=0

We get rid of parentheses

6s-7s-64+64=0

We add all the numbers together, and all the variables

-s=0

s=0/-1

s=0

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