10sin(2x)-7cos(2x)=5

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Solution for 10sin(2x)-7cos(2x)=5 equation:


Simplifying
10sin(2x) + -7cos(2x) = 5

Remove parenthesis around (2x)
10ins * 2x + -7cos(2x) = 5

Reorder the terms for easier multiplication:
10 * 2ins * x + -7cos(2x) = 5

Multiply 10 * 2
20ins * x + -7cos(2x) = 5

Multiply ins * x
20insx + -7cos(2x) = 5

Remove parenthesis around (2x)
20insx + -7cos * 2x = 5

Reorder the terms for easier multiplication:
20insx + -7 * 2cos * x = 5

Multiply -7 * 2
20insx + -14cos * x = 5

Multiply cos * x
20insx + -14cosx = 5

Reorder the terms:
-14cosx + 20insx = 5

Solving
-14cosx + 20insx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-20insx' to each side of the equation.
-14cosx + 20insx + -20insx = 5 + -20insx

Combine like terms: 20insx + -20insx = 0
-14cosx + 0 = 5 + -20insx
-14cosx = 5 + -20insx

Divide each side by '-14osx'.
c = -0.3571428571o-1s-1x-1 + 1.428571429ino-1

Simplifying
c = -0.3571428571o-1s-1x-1 + 1.428571429ino-1

Reorder the terms:
c = 1.428571429ino-1 + -0.3571428571o-1s-1x-1

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