10sin(2x+40)=12

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Solution for 10sin(2x+40)=12 equation:


Simplifying
10sin(2x + 40) = 12

Reorder the terms:
10ins(40 + 2x) = 12
(40 * 10ins + 2x * 10ins) = 12
(400ins + 20insx) = 12

Solving
400ins + 20insx = 12

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-12 + 400ins + 20insx = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 400ins + 20insx = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-3 + 100ins + 5insx) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-3 + 100ins + 5insx)' equal to zero and attempt to solve: Simplifying -3 + 100ins + 5insx = 0 Solving -3 + 100ins + 5insx = 0 Move all terms containing i to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 100ins + 3 + 5insx = 0 + 3 Reorder the terms: -3 + 3 + 100ins + 5insx = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 100ins + 5insx = 0 + 3 100ins + 5insx = 0 + 3 Combine like terms: 0 + 3 = 3 100ins + 5insx = 3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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