10v2-30=-55v

Solution for 10v2-30=-55v equation:

10v^2-30=-55v

We move all terms to the left:

10v^2-30-(-55v)=0

We get rid of parentheses

10v^2+55v-30=0

a = 10; b = 55; c = -30;
Δ = b2-4ac
Δ = 552-4·10·(-30)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-65}{2*10}=\frac{-120}{20}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+65}{2*10}=\frac{10}{20}
=1/2
$