10v2=13v+3

Solution for 10v2=13v+3 equation:

10v^2=13v+3

We move all terms to the left:

10v^2-(13v+3)=0

We get rid of parentheses

10v^2-13v-3=0

a = 10; b = -13; c = -3;
Δ = b2-4ac
Δ = -132-4·10·(-3)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*10}=\frac{-4}{20}
=-1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*10}=\frac{30}{20}
=1+1/2
$