10w(w-2)+10=0

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Solution for 10w(w-2)+10=0 equation: 



10w(w-2)+10=0

We multiply parentheses

10w^2-20w+10=0

a = 10; b = -20; c = +10;
Δ = b2-4ac
Δ = -202-4·10·10
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{20}{20}=1$

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