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10w^2+37w-12=0
a = 10; b = 37; c = -12;
Δ = b2-4ac
Δ = 372-4·10·(-12)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-43}{2*10}=\frac{-80}{20} =-4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+43}{2*10}=\frac{6}{20} =3/10 $
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