10w=(4w+18)/4w

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Solution for 10w=(4w+18)/4w equation: 



10w=(4w+18)/4w

We move all terms to the left:

10w-((4w+18)/4w)=0



Domain of the equation: 4w)!=0

w!=0/1

w!=0

w∈R



We multiply all the terms by the denominator


10w*4w)-((4w+18)=0

Wy multiply elements

40w^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{80}=0$

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