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10x(1-x)=110
We move all terms to the left:
10x(1-x)-(110)=0
We add all the numbers together, and all the variables
10x(-1x+1)-110=0
We multiply parentheses
-10x^2+10x-110=0
a = -10; b = 10; c = -110;
Δ = b2-4ac
Δ = 102-4·(-10)·(-110)
Δ = -4300
Delta is less than zero, so there is no solution for the equation
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