10x(2x-3)=

Solution for 10x(2x-3)= equation:

10x(2x-3)=

We move all terms to the left:

10x(2x-3)-()=0

We add all the numbers together, and all the variables

10x(2x-3)=0

We multiply parentheses

20x^2-30x=0

a = 20; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·20·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*20}=\frac{60}{40}
=1+1/2
$