10x(4x/2)=14

Solution for 10x(4x/2)=14 equation:

10x(4x/2)=14

We move all terms to the left:

10x(4x/2)-(14)=0

We add all the numbers together, and all the variables

10x(+4x/2)-14=0

We multiply parentheses

40x^2-14=0

a = 40; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·40·(-14)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{35}}{2*40}=\frac{0-8\sqrt{35}}{80}
=-\frac{8\sqrt{35}}{80}
=-\frac{\sqrt{35}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{35}}{2*40}=\frac{0+8\sqrt{35}}{80}
=\frac{8\sqrt{35}}{80}
=\frac{\sqrt{35}}{10}
$