10x(5x-2)=0

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Solution for 10x(5x-2)=0 equation:



10x(5x-2)=0
We multiply parentheses
50x^2-20x=0
a = 50; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·50·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*50}=\frac{0}{100} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*50}=\frac{40}{100} =2/5 $

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