10x(6x+8)=80

Solution for 10x(6x+8)=80 equation:

10x(6x+8)=80

We move all terms to the left:

10x(6x+8)-(80)=0

We multiply parentheses

60x^2+80x-80=0

a = 60; b = 80; c = -80;
Δ = b2-4ac
Δ = 802-4·60·(-80)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-160}{2*60}=\frac{-240}{120}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+160}{2*60}=\frac{80}{120}
=2/3
$