10x(7x+5)=0

Solution for 10x(7x+5)=0 equation:

10x(7x+5)=0

We multiply parentheses

70x^2+50x=0

a = 70; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·70·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*70}=\frac{-100}{140}
=-5/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*70}=\frac{0}{140}
=0
$