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10x(x+4)+7(x+4)=0
We multiply parentheses
10x^2+40x+7x+28=0
We add all the numbers together, and all the variables
10x^2+47x+28=0
a = 10; b = 47; c = +28;
Δ = b2-4ac
Δ = 472-4·10·28
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-33}{2*10}=\frac{-80}{20} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+33}{2*10}=\frac{-14}{20} =-7/10 $
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