10x(x+4)=-10

Solution for 10x(x+4)=-10 equation:

10x(x+4)=-10

We move all terms to the left:

10x(x+4)-(-10)=0

We add all the numbers together, and all the variables

10x(x+4)+10=0

We multiply parentheses

10x^2+40x+10=0

a = 10; b = 40; c = +10;
Δ = b2-4ac
Δ = 402-4·10·10
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-20\sqrt{3}}{2*10}=\frac{-40-20\sqrt{3}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+20\sqrt{3}}{2*10}=\frac{-40+20\sqrt{3}}{20}
$