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10x(x-10)=100
We move all terms to the left:
10x(x-10)-(100)=0
We multiply parentheses
10x^2-100x-100=0
a = 10; b = -100; c = -100;
Δ = b2-4ac
Δ = -1002-4·10·(-100)
Δ = 14000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14000}=\sqrt{400*35}=\sqrt{400}*\sqrt{35}=20\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20\sqrt{35}}{2*10}=\frac{100-20\sqrt{35}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20\sqrt{35}}{2*10}=\frac{100+20\sqrt{35}}{20} $
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