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10x(x-2)=90
We move all terms to the left:
10x(x-2)-(90)=0
We multiply parentheses
10x^2-20x-90=0
a = 10; b = -20; c = -90;
Δ = b2-4ac
Δ = -202-4·10·(-90)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{10}}{2*10}=\frac{20-20\sqrt{10}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{10}}{2*10}=\frac{20+20\sqrt{10}}{20} $
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