10x*20x=15

Solution for 10x*20x=15 equation:

10x*20x=15

We move all terms to the left:

10x*20x-(15)=0

Wy multiply elements

200x^2-15=0

a = 200; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·200·(-15)
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{30}}{2*200}=\frac{0-20\sqrt{30}}{400}
=-\frac{20\sqrt{30}}{400}
=-\frac{\sqrt{30}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{30}}{2*200}=\frac{0+20\sqrt{30}}{400}
=\frac{20\sqrt{30}}{400}
=\frac{\sqrt{30}}{20}
$