10x+(6x-3)+141=180

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Solution for 10x+(6x-3)+141=180 equation: 



10x+(6x-3)+141=180

We move all terms to the left:

10x+(6x-3)+141-(180)=0

We add all the numbers together, and all the variables

10x+(6x-3)-39=0

We get rid of parentheses

10x+6x-3-39=0

We add all the numbers together, and all the variables

16x-42=0

We move all terms containing x to the left, all other terms to the right

16x=42

x=42/16

x=2+5/8

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