10x+(6x-3)=180

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Solution for 10x+(6x-3)=180 equation: 



10x+(6x-3)=180

We move all terms to the left:

10x+(6x-3)-(180)=0

We get rid of parentheses

10x+6x-3-180=0

We add all the numbers together, and all the variables

16x-183=0

We move all terms containing x to the left, all other terms to the right

16x=183

x=183/16

x=11+7/16

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