10x+(9-x)=10(9-x)

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Solution for 10x+(9-x)=10(9-x) equation: 



10x+(9-x)=10(9-x)

We move all terms to the left:

10x+(9-x)-(10(9-x))=0

We add all the numbers together, and all the variables

10x+(-1x+9)-(10(-1x+9))=0

We get rid of parentheses

10x-1x-(10(-1x+9))+9=0



We calculate terms in parentheses: -(10(-1x+9)), so:

10(-1x+9)

We multiply parentheses

-10x+90

Back to the equation:

-(-10x+90)



We add all the numbers together, and all the variables

9x-(-10x+90)+9=0

We get rid of parentheses

9x+10x-90+9=0

We add all the numbers together, and all the variables

19x-81=0

We move all terms containing x to the left, all other terms to the right

19x=81

x=81/19

x=4+5/19

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