10x+(9-x)=10(9-x)+x+27

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Solution for 10x+(9-x)=10(9-x)+x+27 equation: 



10x+(9-x)=10(9-x)+x+27

We move all terms to the left:

10x+(9-x)-(10(9-x)+x+27)=0

We add all the numbers together, and all the variables

10x+(-1x+9)-(10(-1x+9)+x+27)=0

We get rid of parentheses

10x-1x-(10(-1x+9)+x+27)+9=0



We calculate terms in parentheses: -(10(-1x+9)+x+27), so:

10(-1x+9)+x+27

We add all the numbers together, and all the variables

x+10(-1x+9)+27

We multiply parentheses

x-10x+90+27

We add all the numbers together, and all the variables

-9x+117

Back to the equation:

-(-9x+117)



We add all the numbers together, and all the variables

9x-(-9x+117)+9=0

We get rid of parentheses

9x+9x-117+9=0

We add all the numbers together, and all the variables

18x-108=0

We move all terms containing x to the left, all other terms to the right

18x=108

x=108/18

x=6

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