10x+12-4x=20+40

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Solution for 10x+12-4x=20+40 equation: 



10x+12-4x=20+40

We move all terms to the left:

10x+12-4x-(20+40)=0

We add all the numbers together, and all the variables

10x-4x+12-60=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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