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10x+1=2(2x-2)+6x+5
We move all terms to the left:
10x+1-(2(2x-2)+6x+5)=0
We calculate terms in parentheses: -(2(2x-2)+6x+5), so:We get rid of parentheses
2(2x-2)+6x+5
We add all the numbers together, and all the variables
6x+2(2x-2)+5
We multiply parentheses
6x+4x-4+5
We add all the numbers together, and all the variables
10x+1
Back to the equation:
-(10x+1)
10x-10x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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