10x+2-2x=8(x+1)-6

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Solution for 10x+2-2x=8(x+1)-6 equation: 



10x+2-2x=8(x+1)-6

We move all terms to the left:

10x+2-2x-(8(x+1)-6)=0

We add all the numbers together, and all the variables

8x-(8(x+1)-6)+2=0



We calculate terms in parentheses: -(8(x+1)-6), so:

8(x+1)-6

We multiply parentheses

8x+8-6

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

8x-8x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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