10x+20(x-5)=290

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Solution for 10x+20(x-5)=290 equation: 



10x+20(x-5)=290

We move all terms to the left:

10x+20(x-5)-(290)=0

We multiply parentheses

10x+20x-100-290=0

We add all the numbers together, and all the variables

30x-390=0

We move all terms containing x to the left, all other terms to the right

30x=390

x=390/30

x=13

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