10x+21(x-3)=340

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Solution for 10x+21(x-3)=340 equation: 



10x+21(x-3)=340

We move all terms to the left:

10x+21(x-3)-(340)=0

We multiply parentheses

10x+21x-63-340=0

We add all the numbers together, and all the variables

31x-403=0

We move all terms containing x to the left, all other terms to the right

31x=403

x=403/31

x=13

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