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10x+3(6x+2)=3(2x+5)+13
We move all terms to the left:
10x+3(6x+2)-(3(2x+5)+13)=0
We multiply parentheses
10x+18x-(3(2x+5)+13)+6=0
We calculate terms in parentheses: -(3(2x+5)+13), so:We add all the numbers together, and all the variables
3(2x+5)+13
We multiply parentheses
6x+15+13
We add all the numbers together, and all the variables
6x+28
Back to the equation:
-(6x+28)
28x-(6x+28)+6=0
We get rid of parentheses
28x-6x-28+6=0
We add all the numbers together, and all the variables
22x-22=0
We move all terms containing x to the left, all other terms to the right
22x=22
x=22/22
x=1
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