10x+3(8+8x)=-6x(x-4)

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Solution for 10x+3(8+8x)=-6x(x-4) equation:



10x+3(8+8x)=-6x(x-4)
We move all terms to the left:
10x+3(8+8x)-(-6x(x-4))=0
We add all the numbers together, and all the variables
10x+3(8x+8)-(-6x(x-4))=0
We multiply parentheses
10x+24x-(-6x(x-4))+24=0
We calculate terms in parentheses: -(-6x(x-4)), so:
-6x(x-4)
We multiply parentheses
-6x^2+24x
Back to the equation:
-(-6x^2+24x)
We add all the numbers together, and all the variables
-(-6x^2+24x)+34x+24=0
We get rid of parentheses
6x^2-24x+34x+24=0
We add all the numbers together, and all the variables
6x^2+10x+24=0
a = 6; b = 10; c = +24;
Δ = b2-4ac
Δ = 102-4·6·24
Δ = -476
Delta is less than zero, so there is no solution for the equation

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