10x+3(8+8x)=-6x(x-4)

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Solution for 10x+3(8+8x)=-6x(x-4) equation: 



10x+3(8+8x)=-6x(x-4)

We move all terms to the left:

10x+3(8+8x)-(-6x(x-4))=0

We add all the numbers together, and all the variables

10x+3(8x+8)-(-6x(x-4))=0

We multiply parentheses

10x+24x-(-6x(x-4))+24=0



We calculate terms in parentheses: -(-6x(x-4)), so:

-6x(x-4)

We multiply parentheses

-6x^2+24x

Back to the equation:

-(-6x^2+24x)



We add all the numbers together, and all the variables

-(-6x^2+24x)+34x+24=0

We get rid of parentheses

6x^2-24x+34x+24=0

We add all the numbers together, and all the variables

6x^2+10x+24=0

a = 6; b = 10; c = +24;
Δ = b2-4ac
Δ = 102-4·6·24
Δ = -476
Delta is less than zero, so there is no solution for the equation

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