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10x+3/2x+5=180
We move all terms to the left:
10x+3/2x+5-(180)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
10x+3/2x-175=0
We multiply all the terms by the denominator
10x*2x-175*2x+3=0
Wy multiply elements
20x^2-350x+3=0
a = 20; b = -350; c = +3;
Δ = b2-4ac
Δ = -3502-4·20·3
Δ = 122260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{122260}=\sqrt{4*30565}=\sqrt{4}*\sqrt{30565}=2\sqrt{30565}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-350)-2\sqrt{30565}}{2*20}=\frac{350-2\sqrt{30565}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-350)+2\sqrt{30565}}{2*20}=\frac{350+2\sqrt{30565}}{40} $
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