10x+3x+2(3x-7)+1-(5-3x)=7-6(1-2x)

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Solution for 10x+3x+2(3x-7)+1-(5-3x)=7-6(1-2x) equation: 



10x+3x+2(3x-7)+1-(5-3x)=7-6(1-2x)

We move all terms to the left:

10x+3x+2(3x-7)+1-(5-3x)-(7-6(1-2x))=0

We add all the numbers together, and all the variables

10x+3x+2(3x-7)-(-3x+5)-(7-6(-2x+1))+1=0

We add all the numbers together, and all the variables

13x+2(3x-7)-(-3x+5)-(7-6(-2x+1))+1=0

We multiply parentheses

13x+6x-(-3x+5)-(7-6(-2x+1))-14+1=0

We get rid of parentheses

13x+6x+3x-(7-6(-2x+1))-5-14+1=0



We calculate terms in parentheses: -(7-6(-2x+1)), so:

7-6(-2x+1)

determiningTheFunctionDomain
-6(-2x+1)+7

We multiply parentheses

12x-6+7

We add all the numbers together, and all the variables

12x+1

Back to the equation:

-(12x+1)



We add all the numbers together, and all the variables

22x-(12x+1)-18=0

We get rid of parentheses

22x-12x-1-18=0

We add all the numbers together, and all the variables

10x-19=0

We move all terms containing x to the left, all other terms to the right

10x=19

x=19/10

x=1+9/10

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