10x+4(4x-3)=(6x+4)+4

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Solution for 10x+4(4x-3)=(6x+4)+4 equation: 



10x+4(4x-3)=(6x+4)+4

We move all terms to the left:

10x+4(4x-3)-((6x+4)+4)=0

We multiply parentheses

10x+16x-((6x+4)+4)-12=0



We calculate terms in parentheses: -((6x+4)+4), so:

(6x+4)+4

We get rid of parentheses

6x+4+4

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

26x-(6x+8)-12=0

We get rid of parentheses

26x-6x-8-12=0

We add all the numbers together, and all the variables

20x-20=0

We move all terms containing x to the left, all other terms to the right

20x=20

x=20/20

x=1

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