10x+4(x-20)=7(4+x)+7x

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Solution for 10x+4(x-20)=7(4+x)+7x equation: 



10x+4(x-20)=7(4+x)+7x

We move all terms to the left:

10x+4(x-20)-(7(4+x)+7x)=0

We add all the numbers together, and all the variables

10x+4(x-20)-(7(x+4)+7x)=0

We multiply parentheses

10x+4x-(7(x+4)+7x)-80=0



We calculate terms in parentheses: -(7(x+4)+7x), so:

7(x+4)+7x

We add all the numbers together, and all the variables

7x+7(x+4)

We multiply parentheses

7x+7x+28

We add all the numbers together, and all the variables

14x+28

Back to the equation:

-(14x+28)



We add all the numbers together, and all the variables

14x-(14x+28)-80=0

We get rid of parentheses

14x-14x-28-80=0

We add all the numbers together, and all the variables

-108!=0

There is no solution for this equation

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