10x+4-8=2(x-1)

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Solution for 10x+4-8=2(x-1) equation: 



10x+4-8=2(x-1)

We move all terms to the left:

10x+4-8-(2(x-1))=0

We add all the numbers together, and all the variables

10x-(2(x-1))-4=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

10x-2x+2-4=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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